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The portion of string between the bridge and upper end of the fingerboard (the part of the string that is free to vibrate) of a...Asked by Jill
The portion of string between the bridge and upper end of the fingerboard (the part of the string that is free to vibrate) of a certain musical instrument is 60.0 cm long [.6m] and has a mass of 2.23 g [.00223kg]. The string sounds an A4 note (440 Hz) when played.
Where must the player put a finger (at what distance from the bridge) to play a D5 note (587 Hz)? For both notes, the string vibrates in its fundamental mode.
x= ?? cm
Without retuning, is it possible to play a G4 note (392 Hz) on this string?
Where must the player put a finger (at what distance from the bridge) to play a D5 note (587 Hz)? For both notes, the string vibrates in its fundamental mode.
x= ?? cm
Without retuning, is it possible to play a G4 note (392 Hz) on this string?
Answers
Answered by
bobpursley
On the A4 note, you know length and frequency. Assume it is in half wave resonacne, so wavelength is twice length. Use the wave equation (f*lambda=velocity) to find velocity.
Then, solve for wavelength on the D5 note, and L must be half that.
Then, solve for wavelength on the D5 note, and L must be half that.
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