A village p is 10km from a point x on a bearing 025degre from x another village Q is 6km from x on a bearing of 162degre.calculate the distance and bearing of p from Q.

Answer 1

you can find the distance PQ using the law of cosines:

x^2 = 10^2 + 6^2 - 2(10)(6)cos137°
x = 14.959

for the bearing, locate P and Q in rectangular coordinates and then the bearing is

90-arctan(y/x)

where x and y are the corresponding displacements from Q to P.

Answer 2

Actually i want the answer to that question and how to solve it thanks.