a vehicle is accelerating on a straight road. Its velocity at any instant is 30 km/hr, after 2 s, it is 33.6 km/hr and after further 2 s, it is 37.2 km/hr. Find the acceleration of vehicle in m/s^2

Answer 1

Here,
u1 = 30 km/h
t = 2 s
u2 = 33.6 km/h
a = (u2 – u1)/t
a1 = (33.6 – 30)/2 = 1.8 ms-2
Similarly, a2 = (37.2 – 33.6)/2 = 1.8 ms-2
The acceleration of the vehicle is 1.8 ms-2

Answer 2

Here,
after 2s, velocity risses with about 3.6 km/hr

so,
3.6/2 = 1.8 km/hr

(1.8*1000)metre per second/(60*60)second

=(5/10)m/s
=0.5m/s

Answer 3

Answer is 0.5m/(s*s)

Answer 4

Here,
u1 = 30 km/h
t = 2 s
u2 = 33.6 km/h
a = (u2 – u1)/t
a1 = (33.6 – 30)/2 = 1.8 ms-2
Similarly, a2 = (37.2 – 33.6)/2 = 1.8 ms-2
The acceleration of the vehicle is 1.8 ms-2
Here,
after 2s, velocity risses with about 3.6 km/hr

so,
3.6/2 = 1.8 km/hr

(1.8*1000)metre per second/(60*60)second

=(5/10)m/s
=0.5m/s
Answer is 0.5m/(s*s)
yes, it is
acceleration uniform

Answer 5

You are genius ..

Answer 6

Answer is 0.5m/ssquare

Answer 7

thank you