A vacuum cleaner has a measured sound level of 75.7 dB. What is the intensity of this sound? Answer in units of W/m^2

Answer 1

B=75.7 dB
I=1x10^-2 W/m^2

B=10 log (I/I°)
I=I°10^3/10=(1x10^-2 W/m^2) 10^7.57
=3.71535x10^-5 W/m^2