A uniform wooden lath 100cm long and a mass 95gis balanced on a knife edge when a 5g mass is hung 10cm from one end. How far is the knife edge from the centre of gravity of the lath

Answer 1

Am requesting for the answer to that question coz I have no idea

Answer 2

Need the solution

Answer 3

My answer is 2 or 2.5

Answer 4

To find the distance of the knife edge from the center of gravity of the lath, we can use the principle of moments. The principle of moments states that for an object to be in equilibrium, the sum of the anticlockwise moments must be equal to the sum of the clockwise moments.

Let's assume that the distance of the knife edge from the center of gravity of the lath is x.

The anticlockwise moment is given by the product of the 5g mass (0.005 kg) and its distance from the knife edge (10 cm = 0.1 m), which is 0.005 x 0.1 = 0.0005 Nm.

The clockwise moment is given by the product of the lath's mass (0.095 kg), its length (100 cm = 1 m), and the distance from the knife edge to the center of gravity (x).

Since the lath is balanced on the knife edge, the anticlockwise moment is equal to the clockwise moment:

0.0005 = 0.095 x 1 x x = 0.095x

Solving this equation for x, we get:

0.095x = 0.0005
x = 0.0005 / 0.095
x ≈ 0.0053 m

So, the knife edge is approximately 0.0053 meters (or 5.3 mm) from the center of gravity of the lath.