A uniform half metre rule is freely pivoted at the 15cm Mark and it balanced horizontally when a body of mass 40g is hung from the 2cm Mark. calculate the mass of the rule
6 answers
Draw a clear force diagram of the arrangements
the center of mass of the rule is at the 25 cm mark
40 g * (15 cm - 2 cm) = M * (25 cm - 15 cm)
40 g * (15 cm - 2 cm) = M * (25 cm - 15 cm)
Since a meter is 1m long which z equal to 100cm,,the half meter rule(simple calculation) is 0.5m or 50cm. Hence,we will b working with the 50cm rule.
Now, the center of mass of a 50cm rule is at 25cm.furthermore,from the data we're told that the object is pivoted at 15cm and the object of 40g is hung at 2cm from the beggining of the rule, hence using the simple formula we will relate the two scenarios which are;
Distance from 2cm to where the pivot is multiplied by mass( 40g*13) must b equal to the distance from the pivot to the center of mass* mass(10*xg).
Doing the simple calculation,the answer has to be 52g
Now, the center of mass of a 50cm rule is at 25cm.furthermore,from the data we're told that the object is pivoted at 15cm and the object of 40g is hung at 2cm from the beggining of the rule, hence using the simple formula we will relate the two scenarios which are;
Distance from 2cm to where the pivot is multiplied by mass( 40g*13) must b equal to the distance from the pivot to the center of mass* mass(10*xg).
Doing the simple calculation,the answer has to be 52g
Auniform half meter rule is pivoted at 15cm mark and balanced horizontally when a body of mass 40g is hanging from the 2cm mark.calculate the mass of the half meter rule
I dnt know
1.1N
2 answers