A uniform chain 10m long and weighing 6 kg permetre hangs vertically.calculate the work required to wind it up..

Question

Plzz solve it

Answer 1

integrate from x = 0 to x = 10
dm/dx = 6 kg/m

F = x * 6 * 9.81
d work = F(x) dx
d work = x (6)(9.81) dx
= (x^2/2) * 6 * 9.81 from 0 to 10
=(100/2)*6*9.81