A mechanic uses a chain and block to lift a 875-kg engine 4.00 m to the top of the garage. The downward force in the chain over the 4.00 m distance is 5.00 x 10^4 N.

A) Calculate the work done in raising the motor
B) How much useful work was done?
C) What is the efficiency of the chain and block pulley in raising the motor?

2 answers

work done = force * distance = 50,000*4 = 200,000 Joules

useful work= m g h = 875*9.81*4 =34,335 J

eff = 100 * 34335/200000 = 17.2%
3500J