A two-slice bread toaster consumes 849.0 W of power when plugged into a 120.0-V source.

Question

(a) What is the current in the toaster?
A

(b) What is the resistance of the coils in the toaster?
Ω

Answer 1

Given P=849.0, V=120.0, I=? and R=?
Using p=IV and I=P/V
I=849.0/120.0
I=7.075A
Putting I= 7.075 into v=it
120.0=7.075xrR
R=120.0/7.075
R=16.96 ohms

Answer 2

V=IR....not it

Answer 3

a. E*I = 849
120*I = 849
I = 7.075A.

b. R = E/I = 120/7.075 = 16.96 ohms.