odd numbers 3 5 7
odd for first = 1/3
then for second 1/2
both 1/6
A two-digit locker combination is made up of two non-zero digits. Digits in a combination are not repeated and range from 3 through 8.
Event A = choosing an odd number for the first digit
Event B = choosing an odd number for the second digit
If a combination is chosen at random, with each possible locker combination being equally likely, what is P(A and B) expressed in simplest form?
A. 1/5
B. 3/14
C. 5/18
D. 2/5
5 answers
but maybe they mean ANY odd number, not a particular one
odd 3,5,7
even 4, 6, 8
first one 3/6 = 1/2
second one 2/5
both 0.2
odd 3,5,7
even 4, 6, 8
first one 3/6 = 1/2
second one 2/5
both 0.2
the answer is maybe D 2/5ths :)
thank you all for the help :)
1/6 love you all have a nice day