P(A) = 1/10
P(B) = P(A)*4/9 + (1-P(A))*5/9
so, what do you think?
A two-digit locker combination is made up of non-zero digits and no digit is repeated in any combination.
Event A = the first digit is 4
Event B = the second digit is odd
If a combination is chosen at random with each possible locker combination being equally likely, what is P(A and B) expressed in simplest form?
A.
B.
C.
D.
1 answer
3 answers