surely you can see that
P(A) = 1/9
P(B) = 4/10
so, what do you think?
Note that saying no digit is repeated is redundant, since A and B are mutually exclusive anyway.
A two-digit locker combination is made up of nonzero digits and no digit is repeated in any combination.
Event A = the first digit is 1
Event B = the second digit is even
If a combination is picked at random with each possible locker combination being equally likely, what is P(A and B) expressed in simplest form?
3 answers
Answer is A
Sorry the Answer is C
C.) 1/2
I found out the hard way :(
C.) 1/2
I found out the hard way :(
8 answers