The velocity immediately after contact is found by
1500*0+5000V=6500V'
So the energy after the collision in motion is 1/2 (6500)V'^2
that must equal (6500)g*mu*distance
1/2 6500 V'^2=6500 g*.7*30
or
V'^2=2g*.7*30
But V'=5000/6500 V
now put that in, and solve for V
A truck of 5000kg hits a car of 1500kg at an intersection. After the collision, both vehicles remained glued together and slid over a distance of 30 meters before coming to a halt. Knowing that the coefficient of kinetic friction between both vehicles and the street is 0.700, find the velocity of the truck before the collision.
2 answers
how do you find this?
1500*0+5000V=6500V'
Thank you for your time
1500*0+5000V=6500V'
Thank you for your time