A triangular-shaped wall has a base of 2x+4 and a height of x+3. The area of the triangle is 56 in^2. What is the value of "x"?

3 answers

A = 1/2bh
52 = 1/2(2x+4)(x +3)
multiply both sides of equation by 2
104 = (2x +4)(x +3)
2+2
-2,-3