solve the given equation for h
rearranging and simplifying ... 0 = h^2 + 2 h - 99
factor or use the quadratic formula
A triangular lot in a park has a base with a measure that is 4 more than twice the height of the lot. The area of the lot is 99 square feet. Since the area of a triangle is found by using the formula A= 1/2bh, the area for this lot can be represented by the equation 99=1/2(2h+4)h, where h represents the height of the triangle.
What is the height of the lot?
Once again, I am not sure what the steps are for figuring out this problem. Someone please give me the steps for solving this problem PLEASE!! thank you
2 answers
99 = 1/2(2h+4)h.
99 = (h+2)h,
99 = h^2 + 2h,
h^2 + 2h - 99 = 0. Solve for h:
h = (-B +- Sqrt(B^2-4AC))/2A.
h = (-2 +- Sqrt(4 + 396))/2,
h = (-2 +- 20)/2 = -1 +- 10 = 9, and -11 Ft.
Use the positive number: h = 9 Ft.
99 = (h+2)h,
99 = h^2 + 2h,
h^2 + 2h - 99 = 0. Solve for h:
h = (-B +- Sqrt(B^2-4AC))/2A.
h = (-2 +- Sqrt(4 + 396))/2,
h = (-2 +- 20)/2 = -1 +- 10 = 9, and -11 Ft.
Use the positive number: h = 9 Ft.
1 answer