To solve for the angles of triangle \( \triangle LMN \) using the given expressions, we first note that the sum of the angles in a triangle is always \( 180^\circ \). Therefore, we set up the equation:
\[ ∠L + ∠M + ∠N = 180^\circ \]
Substituting the expressions for the angles, we have:
\[ (4x + 10) + 2x + 44° = 180° \]
Combining the terms gives:
\[ 6x + 54° = 180° \]
Now, we isolate \( x \):
\[ 6x = 180° - 54° \] \[ 6x = 126° \] \[ x = 21° \]
Now that we have the value for \( x \), we can find the measures of the angles:
\[ ∠L = 4x + 10 = 4(21) + 10 = 84 + 10 = 94° \]
\[ ∠M = 2x = 2(21) = 42° \]
\[ ∠N = 44° \]
Now we have the measures of the angles:
- \( ∠L = 94° \)
- \( ∠M = 42° \)
- \( ∠N = 44° \)
To list the sides in increasing order, we use the fact that the larger the angle, the longer the opposite side. Therefore, we have:
- \( ∠M = 42° \) corresponds to side \( LN \)
- \( ∠N = 44° \) corresponds to side \( LM \)
- \( ∠L = 94° \) corresponds to side \( MN \)
This gives us the following order of the sides based on the angle measures:
\[ LN < LM < MN \]
Thus, the answer is:
LN < LM < MN.