To find the side lengths in increasing order based on the angles of triangle \( \triangle LMN \), we first need to determine the measures of the angles \( \angle L \) and \( \angle M \).
Given: \[ \angle L = 4x + 10 \] \[ \angle M = 2x \] \[ \angle N = 44^\circ \]
Using the fact that the sum of the angles in a triangle is \( 180^\circ \), we can set up the equation: \[ \angle L + \angle M + \angle N = 180^\circ \] Substituting the values we have: \[ (4x + 10) + 2x + 44 = 180 \] Simplifying: \[ 6x + 54 = 180 \] Subtracting 54 from both sides: \[ 6x = 126 \] Dividing by 6: \[ x = 21 \]
Now substituting \( x \) back into the expressions for the angles: \[ \angle L = 4(21) + 10 = 84 + 10 = 94^\circ \] \[ \angle M = 2(21) = 42^\circ \] \[ \angle N = 44^\circ \]
Thus, the angle measures are:
- \( \angle L = 94^\circ \)
- \( \angle M = 42^\circ \)
- \( \angle N = 44^\circ \)
Now, we rank these angles:
- \( \angle M = 42^\circ \)
- \( \angle N = 44^\circ \)
- \( \angle L = 94^\circ \)
In a triangle, the side lengths are opposite to their respective angles. Therefore, the order from the smallest angle to the largest angle gives us the increasing order of the side lengths:
- \( \angle M \) (42°) → side \( LN \)
- \( \angle N \) (44°) → side \( LM \)
- \( \angle L \) (94°) → side \( MN \)
Thus, the side lengths in increasing order are: \[ LN < LM < MN \]
The correct response is: \[ LN < LM < MN \]