A train left town A for town B. The journey took 3 hours 40 minutes. The train arrived at town B at 11:05am, what time did the train leave town A?
2 answers
11:05 - 3:40 = 10:65 - 3:40 = 7:25 AM
11:05 = 11h + 5 min
Train leave town A at:
11h + 5min - ( 3h + 40min ) =
11h - 3 h + 5min - 40 min
5min - 40min = - 35 min
Time cannot be negative, so due to the fact that 1h = 60 min write 11:05 as:
11:05 = 10h + 1h + 5min =
10h + 60min + 5min =
10h + 65min
11h + 5min - ( 3h + 40min ) =
10h + 65min - ( 3h + 40min ) =
10h - 3 h + 65min - 40 min
7h + 25 min
Train leave town A at 7:25 am
Train leave town A at:
11h + 5min - ( 3h + 40min ) =
11h - 3 h + 5min - 40 min
5min - 40min = - 35 min
Time cannot be negative, so due to the fact that 1h = 60 min write 11:05 as:
11:05 = 10h + 1h + 5min =
10h + 60min + 5min =
10h + 65min
11h + 5min - ( 3h + 40min ) =
10h + 65min - ( 3h + 40min ) =
10h - 3 h + 65min - 40 min
7h + 25 min
Train leave town A at 7:25 am
1 answer