train goes 27 t meters
car goes 27 t + 29 meters
so
27 t + 29 = 38 t + (1/2)(2) t^2
A train is moving parallel and adjacent to a highway with a constant speed of 27 m/s. Ini- tially a car is 29 m behind the train, traveling in the same direction as the train at 38 m/s and accelerating at 2 m/s2.
What is the speed of the car just as it passes the train?
Answer in units of m/s
2 answers
N identical resistors are connected in parallel. The resistance of one of them is equal to R. What is the equivalent resistance of all N resistors?
1 answer