a tractor of mass 5.0×10^3kg is used to tow a car of mass 2.5×10^3kg. The tractor moved with a speed of 3.0m/s just before the towing rope became taut.

Question

a tractor of mass 5.0×10^3kg is used to tow a car of mass 2.5×10^3kg. The tractor moved with a speed of 3.0m/s just before the towing rope became taut. 
1. Find the speed of the tractor immediately the rope becomes taut
2. loss in kinetic energy of the system just after the car has started moving 
3. impulse in the rope when it jerks the car into motion

Henry2, · Accepted Answer

Given:
M1 = 5000kg, Vi = 3m/s.
M2 = 2500kg, V2 = 0 before taut.
V3 = Velocity of M1 after taut(tight).

Momentum before taut = Momentum after taut.
M1*V1 = (M1+M2)V3.
5000 * 3 = 7500*V3,
V3 = 2 m/s.

Note: The car is not a part of the system until the rope becomes taut(tight).

Denny krugher · Answer

Define the word; IMPULSE

Benji · Answer

The like are not complete and the solution is in short ways

Ahmad · Answer

I need an answer