A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 3.7 m/s. The car is a distance d away. The bear is 27 m behind the tourist and running at 6.0 m/s. The tourist reaches the car safely. What is the maximum possible value for d?

Answer 1

(x+d)/v2 =d/v1
x•v1=d(v2-v1)
d=x•v1/(v2-v1)=27•3.7/(6-3.7)=43.4 m