A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 4.2 m/s. The car is a distance d away. The bear is 29 m behind the tourist and running at 6.0 m/s. The tourist reaches the car safely. What is the maximum possible value for d?

Answer 1

Distance tourist = d
Distance bear = (d+29)
time the same
time = distance/speed
d/4.2 = (d+29)/6
6 d = 4.2 (d+29)
You take it from there.

Answer 2

68 m