A tire 0.5m in radius rotates at a constant rate of 200 rev/min. find the speed and acceleration of a stone lodged in the tread of the tire (on its outer edge)

Answer 1

C = pi*2r = 3.14 * 1 = 3.14 m.

Vo = 200rev/min * 3.14m/rev. * 1min/60s = 10.5 m/s.

Since the velocity is constant, the acceleration is zero:
a = (V-Vo)/t = (10.5-10.5)/t = 0/t = 0.