A tire 0.500 m in radius rotates at a constant rate of 200 rev/min. Find the speed and acceleration of a small stone lodged in the tread of the tire ( on its outer edge ).

Question

A tire 0.500 m in radius rotates at a constant rate of 200 rev/min. Find the speed and acceleration of a small stone lodged in the tread of the  tire ( on its outer edge ).

Henry · Answer

C = pi * 2r = 3.14 * 1.0 = 3.14 m. = Circumference. V = 200rev/min * 3.14m/rev * 1min/60s = 10.5 m/s.

Anonymous · Answer

May God almighty blessed you more for you help thank you

Anton · Answer

the solution of it.