A thin rod of length 2.35 m and mass 13.9 kg is rotated at an angular speed of 3.75 rad/s around an axis perpendicular to the rod and through its center of mass. Find the magnitude of the rod's angular momentum.

Question

I used the formula ML^2/3 * w and got 95.96 but it tells me it's wrong? I wanted a second opinion.

Answer 1

(1 / 12) m L^2 * omega
rod is spinning around CENTER, not end so 1/12 not 1/3
divide whatever you did by 4