What is the angular momentum of the second hand on a clock if the clock has a length of 25cm, a mass of 20g, and is rotating with constant angular velocity. Treat the second hand as a thin rod.

Answer 1

I w
where I is moment of inertia
and
w is radians/second = 2 pi/period
period = 1 minute = 60 seconds

I = (1/3) M L^2 = (1/3)(.020 Kg)(.25 m)^2
= 4.17*10^-4
4.17 *10^-4 * 2 * pi / 60 = 4.36 * 10^-5