A tetrahedral site in a close-packed lattice is formed by four spheres at the corners of a regular tetrahedron. This is equivalent to placing the spheres at alternate corners of a cube. In such a close-packed arrangement the spheres are in contact and if the spheres have a radius r, the diagonal of the face of the cube is 2r. The tetrahedral hole is inside the middle of the cube. Find the body diagonal of this cube.
Honestly just a formula or procedure on how to solve this will be helpful. My professor does not explain anything to us. I have looked in the book and still have no idea.
2 answers
Did you look at my answer below? Don't post an exact duplicate without acknowledging that answer.
No because i have no idea where your "answer below" is