A test charge of +5.0µC experiences a force of 2.0x103 N[S] when placed at the midpoint of two
oppositely charge parallel plates. Assuming that the plates are electrically isolated and have a
distance of separation of 8.0mm, what will be the force experienced by a different charge of -
2.0µC, located 2.0mm from the negative plate
2 answers
i dont no
E the same the whole way across so it does not matter how far from the plate.
F = Q E
E = voltage difference / distance between plates
so
(2/5) the force on the first one
F = Q E
E = voltage difference / distance between plates
so
(2/5) the force on the first one
4 answers