A tennis player hits a 0.1-kilogram tennis ball with her racket from the north end of a court. Her racket was traveling at 65 kilometers per hour. The ball accelerated at a rate of 10 meters per second squared. The ball hits the floor on the south end of the tennis court. The floor sends the ball toward the tennis player's opponent with the same acceleration. How much force did the floor on the south end of the court exert on the ball?(1 point)

Question

Responses

7.5 N

1 N

6.5 N

0.01 N

Answer 1

To find the force that the floor on the south end of the court exerted on the ball, we can use Newton's second law of motion, which states that \( F = m \cdot a \), where \( F \) is the force, \( m \) is the mass of the object, and \( a \) is the acceleration.

Given:

• Mass of the tennis ball \( m = 0.1 \) kg
• Acceleration \( a = 10 \) m/s²

Now we can calculate the force:

\[ F = m \cdot a = 0.1 , \text{kg} \cdot 10 , \text{m/s}^2 = 1 , \text{N} \]

Therefore, the force that the floor on the south end of the court exerted on the ball is 1 N.