A tennis player hits a 0.1-kilogram tennis ball with her racket from the north end of a court. Her racket was traveling at 65 kilometers per hour. The ball accelerated at a rate of 10 meters per second squared. The ball hits the floor on the south end of the tennis court. The floor sends the ball toward the tennis player's opponent with the same acceleration. How much force did the floor on the south end of the court exert on the ball

Answer 1

To find the force that the floor exerted on the ball, we can use Newton's second law of motion, which states that:

\[ F = ma \]

Where:

• \( F \) is the force,
• \( m \) is the mass of the object,
• \( a \) is the acceleration.

In this case, the mass \( m \) of the tennis ball is given as 0.1 kilograms, and the acceleration \( a \) (after it hits the floor) is also given as 10 meters per second squared (m/s²).

Let's calculate the force:

\[ F = ma = 0.1 , \text{kg} \times 10 , \text{m/s}^2 = 1 , \text{N} \]

Therefore, the force exerted by the floor on the ball is 1 Newton (N).