A tennis player hits a 0.1-kilogram tennis ball with her racket from the north end of a court. Her racket was traveling at 65 kilometers per hour. The ball accelerated at a rate of 10 meters per second squared. The ball hits the floor on the south end of the tennis court. The floor sends the ball toward the tennis player's opponent with the same acceleration.

Question

How much force did the floor on the south end of the court exert on the ball?
(1 point)
6.5 N
• 7.5 N
• 0.01 N
• 1 N

Answer 1

To find the force exerted on the ball by the floor, we can use Newton's second law of motion, which states that \( F = ma \), where \( F \) is the force, \( m \) is the mass, and \( a \) is the acceleration.

Given:

• Mass of the tennis ball, \( m = 0.1 , \text{kg} \)
• Acceleration of the ball, \( a = 10 , \text{m/s}^2 \)

We can plug these values into the formula:

\[ F = m \cdot a \]

\[ F = (0.1 , \text{kg}) \cdot (10 , \text{m/s}^2) \]

\[ F = 1 , \text{N} \]

Therefore, the force exerted by the floor on the ball is 1 N.

So, the correct answer is:

• 1 N