A tennis player hits a 0.1-kilogram tennis ball with her racket from the north end of a court. Her racket was traveling at 65 kilometers per hour. The ball accelerated at a rate of 10 meters per second squared. The ball hits the floor on the south end of the tennis court. The floor sends the ball toward the tennis player's opponent with the same acceleration. How much force did the floor on the south end of the court exert on the ball?(1 point)

Question

Responses

7.5 N
7.5 N

1 N
1 N

6.5 N
6.5 N

0.01 N

Answer 1

To find the force that the floor exerts on the ball, we can use Newton's second law, which states that force is equal to mass times acceleration (F = m * a).

Here, the mass of the tennis ball (m) is 0.1 kg and the acceleration (a) is given as 10 m/s².

Now, we can calculate the force:

\[ F = m \cdot a \]

\[ F = 0.1 , \text{kg} \cdot 10 , \text{m/s}^2 \]

\[ F = 1 , \text{N} \]

Therefore, the force that the floor on the south end of the court exerted on the ball is 1 N.