A tennis player hits a 0.1-kilogram tennis ball with her racket from the north end of a court. Her racket was traveling at 65 kilometers per hour. The ball accelerated at a rate of 10 meters per second squared. The ball hits the floor on the south end of the tennis court. The floor sends the ball toward the tennis player's opponent with the same acceleration. How much force did the floor on the south end of the court exert on the ball?(1 point) Responses 0.01 N 0.01 N 7.5 N 7.5 N 1 N 1 N 6.5 N

Answer 1

To solve for the force exerted by the floor on the tennis ball, we can use Newton's second law, which states that force is equal to mass multiplied by acceleration (F = m * a).

In your scenario:

• The mass (m) of the tennis ball is 0.1 kilograms.
• The acceleration (a) after it hits the floor is given as 10 meters per second squared (10 m/s²).

Now we can apply the formula:

\[ F = m \times a \]

Substituting in the values:

\[ F = 0.1 , \text{kg} \times 10 , \text{m/s}^2 = 1 , \text{N} \]

Therefore, the force exerted by the floor on the ball is 1 N.