To solve this problem, we can use Newton's second law, which states that force (F) is equal to mass (m) times acceleration (a).
First, we need to convert the velocity of the racket from kilometers per hour to meters per second. We can do this by dividing 65 kilometers per hour by 3.6:
65 km/h รท 3.6 = 18.055... m/s
Next, we can calculate the initial force exerted by the racket on the ball using the formula F = m x a:
F = 0.1 kg x 18.055... m/s^2 = 1.8055... N
Since the floor exerts an equal force on the ball as it hits the south end of the court, the force exerted by the floor on the ball is also 1.8055... N.
Therefore, the correct answer is closest to D. 6.5 N.
A tennis player hits a 0.1-kilogram tennis ball with her racket from the north end of a court. Her racket was traveling at 65 kilometers per hour. The ball accelerated at a rate of 10 meters per second squared. The ball hits the floor on the south end of the tennis court. The floor sends the ball toward the tennis player's opponent with the same acceleration. How much force did the floor on the south end of the court exert on the ball?
A. 7.5 N
B. 1N
C. 0.01 N
D. 6.5 N
1 answer