To find the force exerted by the floor on the south end of the court, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
First, we need to convert the mass of the ball from kilograms to grams, since acceleration is given in meters per second squared.
0.1 kilograms * 1000 grams/kilogram = 100 grams
Now, we can calculate the force:
Force = mass * acceleration
Force = 100 grams * 10 meters per second squared
Force = 1000 grams * meters per second squared
Force = 1000 grams * 1 meter per second squared
Force = 1000 grams*m/s^2
Therefore, the force exerted by the floor on the ball is 1000 grams*m/s^2, or 1 Newton (1 N).
A tennis player hits a 0.1-kilogram tennis ball with her racket from the north end of a court. Her racket was traveling at 65 kilometers per hour. The ball accelerated at a rate of 10 meters per second squared. The ball hits the floor on the south end of the tennis court. The floor sends the ball toward the tennis player's opponent with the same acceleration. How much force did the floor on the south end of the court exert on the ball?(1 point) Responses 7.5 N 7.5 N 0.01 N 0.01 N 6.5 N 6.5 N 1 N
1 answer
1 answer