h = 0.5g*t^2 = 2.4-0.91.
4.9t^2 = 1.49. t1 = 0.551 s.
d1 = Xo*t1 = 22.3 * 0.551 = 12.3 m. = Distance from back line to net.
0.5g*t2^2 = 2.4.
4.9t2^2 = 2.4, t2 = 0.70 s. to fall to gnd.
d2 = Xo*t2 = 22.3 * 0.7 = 15.6 m. = Maximum distance travelled.
a. Yes.
b. d = 12.3 + 6.4 = 18.7 m. available. Yes.
A tennis ball is served from the back line of the court such that it leaves the racket 2.4 m above the ground in a horizontal direction at a speed of 22.3 m/s. (a) will the ball cross a 0.91-m-high net in front of the server? Will the ball land in the service court, which is within 6.4 m if the net on the other side of the net
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