A symmetric projectile spends a total of 20 seconds in the air. It reaches a peak height of 8 meters. HOw long it takes to reach its peak height? The projectile has a range of 80 meters.What is its horizontal velocity? What is the projectile's horizontal acceleration? What is the projectile's vertical acceleration?

Question

A symmetric projectile spends a total of 20 seconds in the air.  It reaches a peak height of 8 meters.  HOw long it takes to reach its peak height?  The projectile has a range of 80 meters.What is its horizontal velocity?  What is the projectile's horizontal acceleration?  What is the projectile's vertical acceleration?

Henry · Answer

Tr = 20/2 = 10 s. = Rise time. Range = Xo * T = 80 m. Xo * 20 = 80 Xo = 4 m/s = Hor. component of initial velocity. a = 0 = Hor. acceleration. a = g = 9.81 m/s^2. = Ver. acceleration.