To find the probability of selecting an employee who eats breakfast or lunch at the office, we need to first determine the total number of employees who eat either breakfast or lunch or both.
Total employees who eat breakfast = 20
Total employees who eat lunch = 50
Total employees who eat both breakfast and lunch = 15
Total employees who eat breakfast or lunch = Total employees who eat breakfast + Total employees who eat lunch - Total employees who eat both breakfast and lunch
= 20 + 50 - 15
= 55
Therefore, the probability of selecting an employee who eats breakfast or lunch at the office is 55/80 = 0.6875 or 68.75%.
This is because out of the total of 80 employees, 55 of them eat breakfast or lunch or both at the office.
A survey of 80 employees was conducted asking about which Mills they regularly eat at the office. 20 employees eat breakfast at the office, 50 eat lunch, and 15 eat both breakfast and lunch. If an employee is randomly selected from the group, what is the probability of randomly selecting an employee who eat breakfast or lunch at the office? Explain how you got the answer.
1 answer