a survey of 80 employees was conducted asking about which meals they regularly eat at the office twenty employees eat breakfast at the office 50 eat lunch and 15 eat both breakfast and lunch if an employees is randomly selected from this group what is the the probability of randomly selecting a employees who eat breakfast or lunch at the office explain as simplified fraction

1 answer

To find the probability of randomly selecting an employee who eats breakfast or lunch at the office, you need to determine the total number of employees who eat breakfast, lunch, or both.

20 employees eat breakfast
50 employees eat lunch
15 employees eat both breakfast and lunch

To avoid double counting the employees who eat both meals, you need to subtract them from the total count.

Total employees who eat breakfast or lunch = 20 + 50 - 15 = 55

Therefore, the probability of randomly selecting an employee who eats breakfast or lunch at the office is 55 out of 80 employees, which can be simplified to the fraction 11/16.

So, the probability is 11/16.