A Studet walked 4km due east and the 15km east of north in direaction of 37° north of east.finally he walked due north for 3km.how much is displacement.

Answer 1

starting at (0,0) the student walked to
(x,y) = (4+15sin37° , 15cos37°+3)
the displacement is √(x^2+y^2)
in the direction NθE where tanθ = x/y

Answer 2

Teachers

Answer 3

To teach the students in different ways.