East:
E = 4 + 15 cos 37
North:
N = 3 + 15 sin 37
d = sqrt (E^2+N^2)
angle A clockwise from north
tan A = E / N
A student walked 4 km due east and then 15km in a direction of 37° north of east ,finally the walked due north for 3km ,how much is this displacement?
4 answers
0972209372
18.4km
20km