A student was asked to make some copper(II) sulfate-5-5 (CuSO4.5(H2O) BY reacting copper(II) oxide (CuO) with sulfuric acid.

Question

a) Calculate the molar mass of the copper (II) sulfate-5-water
which is (64+32+64) + (10+80)=250 mol

b)Calculate the amount (in mol) of copper (II) sulfate-5-water in a 10,0g sample?

C) Calculate the mass of copper (II) oxide needed to make the 10,0g sample?

Can anyone help me with question b,c??

Answer 1

Amount of moles= mass/molar mass
No. of moles= 10.0g/250 g
No. of moles= 0.04 moles

c) CuO + H2SO4 ----> CuSO4 + H2O
mol 1 1 1 1

1 mole of CuO = 1 mole of CuSO4.5H2O
CuO= 64g + 16g= 80g

80 g of CuO = 250 g of CuSO4
x = 10g of CuSO4

10g x 80g/250g
800g/250
=3.2 grams of CuO

Answer 2

thanks you very much.