A student was asked to prepare a sample of copper(ii)sulphate crystals(CUSO4.5H2O) given 5g of of copper (ii)oxide (CUO) as the starting material.if 10g of dry crystals of CUSO4.5H2O were obtained,calculate the percentage yield???

Answer 1

Convert 5 g CuO to grams CuSO4.5H2O.
That s 5 g CuO x (molar mass CuSO4.5H2O/molar mass CuO) = ?g CuSO4.5H2O equivalent. This is the theoretical yield (TY). The actual yield (AY) from the problemn is 10g.
%yield = (AY/TY)*100 = ?