A student walks 5km due north from O and then 8km due east. Find his bearing from O.Correct to the nearest degrees.

Answer 1

x = 8
y = 5
tan angle above x (east) axis = 5/8
so angle above east axis = 32 degrees north of east
so 90 - 32 = 58 degrees compass bearing East of North

Answer 2

Disp. = 5i+6
Tan A = x/y = 6/5.
A = 50 deg. CW from +y-axis.

Answer 3

Thanks for your time