a student walks 180m in 155s. the student stops for 35s and then walks 320m farther in 145s. What is the average speed of the entire walk?

2 answers

he walked 180+320 m
time elapsed: 155+35+145 s

avg speed= distance/time elapsed
1.49 m/s
Similar Questions
  1. d = 0.08t^2 - 1.6t + 9A student stands facing a motion detector. He quickly walks toward the detector, slows down, stops and
    1. answers icon 3 answers
  2. d = 0.08t^2 - 1.6t + 9A student stands facing a motion detector. He quickly walks toward the detector, slows down, stops and
    1. answers icon 1 answer
  3. d = 0.08t^2 - 1.6t + 9A student stands facing a motion detector. He quickly walks toward the detector, slows down, stops and
    1. answers icon 1 answer
  4. D = 0.08t^2 - 1.6t + 9Why does this equation above fits this model: A student stands facing a motion detector. He quickly walks
    1. answers icon 2 answers
more similar questions