0.5g*t^2 = 25 m.
4.9*t^2 = 25, t^2 = 5.1, t = 2.26 s.
Y = Yo + g*t = 0 + 9.8*2.26 = 22.1 m/s. = Ver. component of final velocity.
V = 16 + 22.1i = 27.3m/s[54.1o].
A student stands at the edge of a cliff and throws a stone horizontally over the edge with a speed of 16.0 m/s. The cliff is h = 25.0 m above a flat horizontal beach, as shown in the figure below.
How long after being released does the stone strike the beach below the cliff?
s
With what speed and angle of impact does the stone land?
m/s
° below the horizontal
1 answer
2 answers