a) how long does it take something to fall 25m?
hf=hi+vi*t-4.9t^2
hf=0, hi=25, vi=0 (vertical velocity), solve for time t.
speed: v=sqrt(vhorital^2+vf'^2)
where vf'=final vertical speed
= -9.8*timefalling
angle, measured from the horizontal, = arc (vf'/vh)
A student stands at the edge of a cliff and throws a stone horizontally over the edge with a speed of 16.0 m/s. The cliff is h = 25.0 m above a flat horizontal beach, as shown in the figure below.
How long after being released does the stone strike the beach below the cliff?
s
With what speed and angle of impact does the stone land?
m/s
° below the horizontal
2 answers
for the first part i got 2.26 seconds,
but for the: WHAT SPEED AND ANGLE OF IMPACT DOES THE STONE LAND?
IM NOT GETTING THE RIGHT ANSWER FOR THE SPEED WITH THE CALCULATION IM GETTING -22.2M/S WHICH IS WRONG. AND SO IS THE ANGLE.
but for the: WHAT SPEED AND ANGLE OF IMPACT DOES THE STONE LAND?
IM NOT GETTING THE RIGHT ANSWER FOR THE SPEED WITH THE CALCULATION IM GETTING -22.2M/S WHICH IS WRONG. AND SO IS THE ANGLE.