A student holds a water balloon outside of an open window and let's go. The window is 10 meters above the ground, and the balloon is falling under the acceleration of gravity, which is 9.8 m/s2. If t=1 sec, what is the distance?

Answer 1

To find the distance traveled by the water balloon after 1 second, we can use the equation of motion:

distance = initial velocity * time + (1/2) * acceleration * time^2

Since the water balloon is being dropped from rest, the initial velocity is 0 m/s. We can substitute the given values into the equation:

distance = 0 * 1 + (1/2) * (9.8) * (1^2)
distance = 0 + (1/2) * (9.8) * 1
distance = 0 + 4.9
distance = 4.9 meters

Therefore, the distance traveled by the water balloon after 1 second is 4.9 meters.