A student drops an object weighing 10.89 g into a 100.00 mL of ethanol in a measuring cylinder. An unknown volume of ethanols pills out which is equal to the volume of the object. The volume of the ethanol remaining in the measuring cylinder in now 73.20 mL. Calculate the density of the object in g/L.

Question

148.77 g/L

0.15 g/L

406.34 g/L

108.90 g/L

Answer 1

To solve this problem, we need to use the formula:

density = mass / volume

First, we need to find the volume of the object, which is equal to the volume of the ethanol that spilled out. We can calculate this by subtracting the final volume of the ethanol (73.20 mL) from the initial volume (100.00 mL):

volume of object = 100.00 mL - 73.20 mL
volume of object = 26.80 mL

Next, we need to convert the volume of the object from milliliters to liters, since the density formula requires units in g/L:

volume of object = 26.80 mL / 1000 mL/L
volume of object = 0.02680 L

Now, we can calculate the density of the object by dividing its mass by its volume:

density = mass / volume
density = 10.89 g / 0.02680 L
density = 406.34 g/L

Therefore, the density of the object is 406.34 g/L. The correct answer is C.