A student drops an object weighing 10.89 g into a 100.00 mL of ethanol in a measuring cylinder. An unknown volume of ethanol spills out which is equal to the volume of the object. The volume of the ethanol remaining in the measuring cylinder in now 73.20 mL. Calculate the density of the object in g/L.

Question

0.15 g/L

148.77 g/L

406.34 g/L

108.90 g/L

Answer 1

First, we need to find the volume of the object:

Volume of spilled ethanol = Volume of object

Volume of object = 100.00 mL - 73.20 mL = 26.80 mL

Next, we can calculate the density of the object using the formula:

Density = mass/volume

We have the mass of the object (10.89 g) and we just found the volume (26.80 mL), but we need to convert the volume to liters:

26.80 mL x 1 L/1000 mL = 0.0268 L

Now we can plug in the values:

Density = 10.89 g/0.0268 L = 406.34 g/L

So the density of the object is 406.34 g/L. Answer: \boxed{406.34 \text{ g/L}}.